You want a negative lookbehind assertion. like so:
#!/usr/bin/php -q
<?
$string = "hello\nworld\n";
$string = preg_replace("/(?<!\r)\n/i","\r\n",$string);
$string = addcslashes($string, "\r\n");
print $string;
?>
Otherwise you're matching any character before a \n that's not a \r and
replacing it.
jonner
On Thu, 2004-07-01 at 16:54, Josh Close wrote:
> I'm trying to get a simple regex to work. Here is the test script I have.
>
> #!/usr/bin/php -q
> <?
>
> $string = "hello\nworld\n";
> $string = preg_replace("/[^\r]\n/i","\r\n",$string);
> $string = addcslashes($string, "\r\n");
>
> print $string;
>
> ?>
>
> This outputs
>
> hell\r\nworl\r\n
>
> so it's removing the char before the \n also.
>
> I just want it to replace a lone \n with \r\n
>
> -Josh
>
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jonathon jongsma
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